9x^2+16=(3x+4)(3x-4)

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Solution for 9x^2+16=(3x+4)(3x-4) equation: 



9x^2+16=(3x+4)(3x-4)

We move all terms to the left:

9x^2+16-((3x+4)(3x-4))=0

We use the square of the difference formula

9x^2+9x^2+16+16=0

We add all the numbers together, and all the variables

18x^2+32=0

a = 18; b = 0; c = +32;
Δ = b2-4ac
Δ = 02-4·18·32
Δ = -2304
Delta is less than zero, so there is no solution for the equation

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